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A still block slides over a still surface,if the mass of the pot is 2.00kg what is the force of friction opposing the motion?coefficient of kinetic friction is taken as 0.42.Gravity is 9.8

  • physics -

    Wb = mg = 2.0kg * 9.8N/kg = 19.6N. =
    Weight of block.

    Fb = 19.6N @ 0deg.
    Fv = 19.6cos(0) = 19.6N. = Force perpendicular to the surface.

    Fk = u*Fv = 0.42*19.6 = 8.23N. = Force of kinetic friction.

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