Chemistry

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Calculate the pH of a 0.053 M (C2H5)2NH solution (Kb = 1.3 10-3).

  • Chemistry -

    ..........B2NH + HOH ==> B2NH2^+ + OH^-
    initial....0.053..........0.........0
    change....-x..............x.........x
    equil.....0.053-x.........x..........x

    Kb = (B2NH^+)(OH^-)/(B2BH)
    Substitute into Kb expression and solve for x (which is OH^-). Convert to pH.

  • Chemistry -

    2.13

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