posted by Mathieu .
A chemist has two ethylene glycol and water solutions: one that contains 11.98% ethylene glycol and another with 7.30% ethylene glycol.
How many litres of each must be mixed to make 7.50 x 102 L containing 10.50% ethylene glycol?
7.5x102 = 765
let the amount of 11.98% mixture be x
let the amount of 7.3% mixture be 765-x
.1198x + .073(765-x) = .105(765)
solve for x