Calculus
posted by Tracy .
Find the area in the first quadrant bounded by the arc of the circle described by the polar equation
r = (2 sin theta)+(4 cos theta)
A. 5pi/2
B. (5pi/2)+4
C. 5pi
D. 5pi + 8

Recall that in polar coordinates,
A = Int(1/2 r^2 dθ)
r^2 = 4 sin^2θ + 8sinθcosθ + 16cos^2θ
= 4 + 4sin2θ + 12cos^2θ
= 10 + 4sin2θ + 6cos2θ
A = Int(5 + 2sin2θ + 3cos2θ)dθ [0,pi/2]
= 5t  cos2θ + 3/2 sin2θ [0,pi/2]
= [5pi/2 + 1 + 0]  [0  1 + 0]
= 5pi/2 + 2