PreCalculus
posted by Helga .
It may look lame but I can't work out how to solve (9) sqrt(4x^2) = 4x + 5sqrt2. I need some guidance, please.

PreCalculus 
drwls
First divide both sides by 9
sqrt(4x^2) = 0.444x  0.1571
Then square both sides and solve the resulting quadratic equation
Respond to this Question
Similar Questions

Physics
*I am lost on a bunch of different problems, and this is one of them. Please note that I am NOT asking for final answers, just some guidance so that I can figure out how to do the problem!!! I know that a lot of times on this site … 
Physics
*I am lost on a bunch of different problems, and this is one of them. Please note that I am NOT asking for final answers, just some guidance so that I can figure out how to do the problem!!! I know that a lot of times on this site … 
Physics
*I am lost on a bunch of different problems, and this is one of them. Please note that I am NOT asking for final answers, just some guidance so that I can figure out how to do the problem!!! I know that a lot of times on this site … 
Inequality
When I solve the inquality 2x^2  6 < 0, I get x < + or  sqrt(3) So how do I write the solution? 
algebra
Can someone please check my work on this problem? 
some algebra help (radicals)
I hope I am writing this down right.. I am trying to do some practice questions to learn 10^5 (sqrt)2y  4^5 (sqrt)2y I am trying to figure out how to solve this They gave us some answers to choose from, but I am clueless on how to … 
Math Help please!!
Could someone show me how to solve these problems step by step.... I am confused on how to fully break this down to simpliest terms sqrt 3 * sqrt 15= sqrt 6 * sqrt 8 = sqrt 20 * sqrt 5 = since both terms are sqrt , you can combine … 
Calculus
Please look at my work below: Solve the initialvalue problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/ Sqrt(4^24(1)(6)))/2(1) r=(16 +/ Sqrt(8)) r=8 +/ Sqrt(2)*i, alpha=8, Beta=Sqrt(2) y(0)=2, e^(8*0)*(c1*cos(0)+c2*sin(0))=c2=2 … 
Precalculus
Can someone please help me with this problem.. I don't get it! Solve (sqrt 5r  9)3 = sqrt(r+4)2 
Math
Find of g(f(x)) when f(x)=sqrt(x+3) and g(x)=(x^2+2)/x. a. g(f(x))=(x^2+2)(sqrt(x+3))/x b. g(f(x))=(x+5)/(sqrt(x+3)) c. g(f(x))=(x^2+6x+11)/(sqrt(x+3)) d. g(f(x))=(sqrt(((x^2+2)/x)+3) Every time I work this problem, I get some crazy …