calculus
posted by Alan
find the rms value of the function
i=15(1e^1/2t) from t=0 to t=4

Steve
If we let r = rms of f(t), then
4r^2 = Int(15  15e^1/2t)[0,4]
= 15t + 30e^(t/2)[0,4]
= [60 + 30/e^2]  [0 + 30]
= 60 + 30/e^2  30
= 30 + 30/e^2
=34.06
so, r = 2.92
see wikipedia on root mean square
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