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I'm having a had time with this problem. Could you please help with step by step resolution?

e^-x / e^-1 + 3 dx

Thank you..

  • Pre-Calculus -

    The "dx" at the end makes me think you are supposed to integrate
    [e^-x / e^-1] + 3 .

    But that would make it a calculus, not a precalculus, question.

    It is not clear what the question is. In any case,
    e^-x / e^-1 = e^(1-x)

    The integral of
    e^(1-x) + 3 dx is
    -e^(1-x) + 3x + C

  • Pre-Calculus -

    Thank you. You helped greatly.

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