Calculus
posted by Tracy .
Evaluate the integral sin4x cos^2 4x dx
A. cos^3 4x/3 +C
B.  cos^3 4x/3 +C
C. cos^3 4x/12 +C
D. cos^3 4x/12 +C

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integrate sin(4x) cos^2(4x) dx
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Notice that the derivative of the power cos^2 (4x) shows up as multiple, so we can just reverse the chain rule
I know that it must be something like (cos 4x)^3....
so from y ' = sin 4x (cos 4x)^2
we get y = sin 4x (cos 4x)^3 (1/3) (1/sin 4x) (1/4)
= (1/12) cos^3 (4x) )
which if you had used brackets correctly would have been C>
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