Calculus

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Evaluate the integral sin4x cos^2 4x dx

A. cos^3 4x/3 +C

B. - cos^3 4x/3 +C

C. cos^3 4x/12 +C

D. -cos^3 4x/12 +C

  • Calculus -

    Go on: wolframalpha dot com

    When page be open in rectangle type:

    integrate sin(4x) cos^2(4x) dx
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    After few seconds when you see result click option: Show steps


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  • Calculus -

    Notice that the derivative of the power cos^2 (4x) shows up as multiple, so we can just reverse the chain rule

    I know that it must be something like (cos 4x)^3....

    so from y ' = sin 4x (cos 4x)^2
    we get y = sin 4x (cos 4x)^3 (1/3) (-1/sin 4x) (1/4)
    = (-1/12) cos^3 (4x) )

    which if you had used brackets correctly would have been C>

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