A hockey player is skating at 17 m/s comes to a complete stop in 2 m. What is the acceleration of the hockey player ?
To find the acceleration of the hockey player, we will use the following equation:
Final velocity (Vf) = Initial velocity (Vi) + (Acceleration × Time)
In this case, the hockey player's final velocity is 0 m/s (as they come to a complete stop), the initial velocity is 17 m/s, and the distance traveled is 2 m. We can assume the time it takes for the player to stop is constant and can be calculated using the equation for uniform acceleration:
Distance (d) = Initial velocity (Vi) × Time (t) + (1/2) × Acceleration (a) × Time (t)^2
Since we know the distance is 2 m and the initial velocity is 17 m/s, we can write:
2 m = 17 m/s × t + (1/2) × a × t^2
Simplifying this equation, we get:
2 m = 17 m/s × t + (1/2) × a × t^2
0 = 17 t + 0.5 a t^2
Now, we need another equation to solve for the acceleration. We know that when the hockey player comes to a stop, the final velocity is 0 m/s. So we have:
Vf = Vi + (Acceleration × Time)
0 m/s = 17 m/s + (Acceleration × t)
Rearranging this equation, we get:
Acceleration × t = -17 m/s
Acceleration = -17 m/s ÷ t
Now we can substitute this equation for acceleration in the previous equation:
0 = 17 t + 0.5 × (-17 m/s ÷ t) × t^2
Simplifying further:
0 = 17 t - 8.5 t
0 = 8.5 t
To find the acceleration, we need to know the value of t, the time it takes for the player to stop. Unfortunately, you did not provide this information, so it is not possible to determine the exact value of the acceleration without this additional data.