precalculus
posted by mz tee .
solve the equation in the complex number system
x^4+x^3+4x^2+10x60=0

try x = 2
16+8+16 +20  60 = 0 sure enough x = 2 works
so divide by (x2)
x^3 + 3 x^2 + 10 x + 30
write as
x^3+10 x +3(x^2 +10)
x(x^2+10) + 3(x^2+10)
(x+3)(x^2+10)
so
x = 3 is a root
left with x^2 = 10
x = +/ i sqrt(10)
so
2, 3, i sqrt 10 , i sqrt 10
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