(2x+1)^2 +4=0
solve the equation. help please :(
(2x+1)^2 = -4
Something squared cannot be negative.
There is no solution to your equation in the set of real numbers
If you accept complex roots ....
2x+1 = ± √-4 = ± 2i
2x = -1 ± 2i
x = (-1 ± 2i)/2