posted by Lilly .
How much work did the movers do (horizontally) pushing a 130kg crate 10.1 m across a rough floor without acceleration, if the effective coefficient of friction was 0.50?
Wc = 130kg * 9.8N/kg = 1274N.
Fc = 1274N @ 0deg.
Fp = 1274sin(0) = 0 = Force parallel to
Fv = 1274cos(0) = 1274N. = Force perpendicular to floor.
Ff = u*Fv = 0.5 * 1274 = 637N. = Force
Fn = Fap - Fp - Ff = ma = 0. a = 0.
Fap - 0 - 637 = 0,
Fap = 637N. = Force applied.
Work = Fd = 637 * 10.1 = 6434J.