chemistry
posted by Monique .
I need help calculating [H3O] from pH and the pOH scale
using my calculator. I have a TI30XIIS

Given pH = 4.67, pH = ?
pH = log(H^+)
4.67 = log(H^+)
4.67 = log(H^+)
(H^+) = 2.29E5
Here is how you do it on the calculator.
Punch in 4.67. Hit the change sign to it becomes . (If you don't have a change sign, punch in 4.67 at the start.)
Now locate and hit the 10^{x} key. That should return 2.29086E5 which can be rounded.
For pOH, the easy way, if you have pH, is
pH + pOH = pKw = 14
So 14=pH = pOH.
If you have OH^ already, then
pOH = log(OH^) and it works just like the pH does. By the way, if you need pKa, it works just like pH and pOH, pKa = log Ka. pKb = log Kb.
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