Post a New Question

chemistry

posted by .

a 25.0ml dsmplr og 0.105M HCI was titrated with 31.5ml of NaOH. What is the concentration of the NaOH
I got 0.0834M am I correct
HCI + NaOH -----> H20 + NaCl
25.0ml HCI x 1L/1000mlx0.105 mol HCI/1L HCI X 1 mol NaOH/ I mol HCI = 0.0834M

  • chemistry -

    My calculator reads 0.0833333 which I would round to 0.0833 and not 0.0834.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question