Algebra
posted by Kelly .
During the first part of a trip a canoeist travels 49 miles at a certain speed. The canoeist travels 25 miles on the second part of the trip at a speed of 5mph slower. The total time for the trip is 5hrs. What was the speed on each part of the trip?

speed on first part  x mph
time for first part = 49/x hrs
speed of second part = x5 mph , where x > 5
time for second part = 25/(x5)
49/x + 25/(x5) = 5
multiply by x(x5)
49(x5) + 25x = 5x(x5)
49x  245 + 25x = 5x^2  25x
5x^2  99x + 245 = 0
x = (99 ± √4901)/10
= 16.9 or 2.9 but x > 5
on the first trip he went at 16.9 mph and on the second part 11.9 mph
WoW! 16.9 mph in a canoe!!
I am a canoist, don't know anybody who can paddle that fast. 
Thank you!