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Algebra

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During the first part of a trip a canoeist travels 49 miles at a certain speed. The canoeist travels 25 miles on the second part of the trip at a speed of 5mph slower. The total time for the trip is 5hrs. What was the speed on each part of the trip?

  • Algebra -

    speed on first part --- x mph
    time for first part = 49/x hrs

    speed of second part = x-5 mph , where x > 5
    time for second part = 25/(x-5)

    49/x + 25/(x-5) = 5
    multiply by x(x-5)
    49(x-5) + 25x = 5x(x-5)
    49x - 245 + 25x = 5x^2 - 25x
    5x^2 - 99x + 245 = 0
    x = (99 ± √4901)/10
    = 16.9 or 2.9 but x > 5

    on the first trip he went at 16.9 mph and on the second part 11.9 mph

    WoW! 16.9 mph in a canoe!!
    I am a canoist, don't know anybody who can paddle that fast.

  • Algebra -

    Thank you!

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