posted by .

Solve the Trigonometric equation for all solutions between [0,360)degrees.

Sinx + 1 = 2.6635

• trig -

.

Since sin(x) is never greater than 1, there is no value of x where sin(x)+1 > 2

## Similar Questions

1. ### Trig.

Can someone please help me with this? Find all solutions to the equation in the interval [0,2pi) cos2x=sinx I know I have to use some sort of identity, but I have no idea how to go about to solve this.

Solve the Trigonometric equation for all solutions between [0,360)degrees. 2Sinx + 1 = 2.6635. Solve for x. does x equal 56.28degrees and 123.72degrees?
4. ### Trig Help

Prove the following: [1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)] =[sinx+sin^2x]/[sinx+1] =[sinx+(1-cos^2x)]/[sinx+1] =?
5. ### Trigonometry

Solve the equation cos^2A = sin^2A + sinA when 0¨¬¡A¡360¨¬. Select all the solutions from the list below. A. 330 degrees B. 270 degrees C. 150 degrees D. 30 degrees
6. ### Math help please last question

Solve the equation. 10. 2(4x -4) + 2(3x + 2) = 360 Can you please help me on this problem?