Calculus
posted by Nyke .
Find an equation of the tangent line to the curve at the given point.
y = sin(sin x), (pi, 0)

Nothing simpler...
y = sin(sin x)
y' = cos(sin x)*cos x
y'(pi) = cos(0)*cos(pi) = 1(1) = 1
so, you want the line through (pi,0) with slope = 1
(y0)/(xpi) = 1
y = pi  x
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