One right triangle has legs 18cm and 14cm. Another right trangle has legs 14cm and 24 cm. What is the ratio of the areas of these two triangles?
A!/A2 = (a1*b1) / (a2*b2),
A1/A2 = (18*14) / (14*24) = 0.75.
To find the ratio of the areas of two right triangles, we can use the formula:
Area of triangle = (base * height) / 2
Let's calculate the area of the first triangle with legs 18 cm and 14 cm:
Area1 = (18 * 14) / 2
= 252 / 2
= 126 cm²
Now, let's calculate the area of the second triangle with legs 14 cm and 24 cm:
Area2 = (14 * 24) / 2
= 336 / 2
= 168 cm²
The ratio of the areas of these two triangles can be found by dividing the area of the first triangle by the area of the second triangle:
Ratio = Area1 / Area2
= 126 / 168
= 0.75
Therefore, the ratio of the areas of these two triangles is 0.75.