posted by Anonymous .
A sample of air from the basement of a home is found to
contain 8.3 ppm of radon. What is the partial pressure of radon
in the basement if the total pressure is 755 torr?
I assume that is 8.3 ppm v/v; if so I would convert that to percent.
(8.3E-6 L/10^6 L)* 100 = mole percent = about 8.3E-10%. Convert that to a fraction (divide by 100) to give mole fraction Rn_, then
pRn = XRnPtotal
I erred here. 8.3 ppm should be expressed as 8.3E-6 mole fraction Rn.