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A 75g person on skis is going down a hill sloped at an angle 30.the coefficient of kinetic friction between the skis and the snow is 0.15.how fast is the skier going 10s after starting from rest?

  • physics -

    First determine the acceleration, a.
    The net force down the slope equals M*a. The net force is the gravity component down the slope minus the friction force.
    M*g*sin30 - M*g*cos30*0.15 = M*a

    M cancels out, and so
    a = g*(sinA -0.15 cosA) = 0.37 g
    = 3.6 m/s^2

    Then use V = a*t for the velocity at time t.

  • physics -

    titties

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