posted by Anonymous .
A 75g person on skis is going down a hill sloped at an angle 30.the coefficient of kinetic friction between the skis and the snow is 0.15.how fast is the skier going 10s after starting from rest?
First determine the acceleration, a.
The net force down the slope equals M*a. The net force is the gravity component down the slope minus the friction force.
M*g*sin30 - M*g*cos30*0.15 = M*a
M cancels out, and so
a = g*(sinA -0.15 cosA) = 0.37 g
= 3.6 m/s^2
Then use V = a*t for the velocity at time t.