Algebra
posted by Megan .
Two hoses are connected to a swimming pool. Working together, they can fill the pool in 4 hr. The larger hose, working alone, can fill the pool in 6 hr less time than the smaller one. How long would it take the smaller one, woking alone, to fill the pool?
Please explain

If small = s, big = b, sb = both, then
1/sb = 1/s + 1/b
1/4 = 1/s + 1/6
1/12 = 1/s
s = 12 hours 
Thank you!

Yeah. Too bad I did it wrong. I read "6 hours" rather than "6 hours less".
It's been done correctly later on. 
See the solution to the problem posted Nov 5 at 10:18 pm
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