Algebra II

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The resultant of two forces of 1120 N and 2210 N is 2870 N. What angle does the resultant make with each of the two forces?

  • Algebra II -

    Draw a triangle ABC with
    AB = 1120
    BC = 2210
    AC = 2870

    You want angles CAB and ACB. In other words, angles A and C

    using the law of cosines,

    2820^2 = 1120^2 + 2210^2 - 2(1120)(2210) cosB

    Now, knowing cos B,

    sinA/2210 = sinB/2870 = sinC/1120

    sinA = 2210*sinB/2870
    sinC = 1120*sinB/2870

    Done.

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