Calculus
posted by Nyke .
In this exercise, we estimate the rate at which the total personal income is rising in a metropolitan area. In 1999, the population of this area was 942,200, and the population was increasing at roughly 9100 people per year. The average annual income was $34,549 per capita, and this average was increasing at about $1400 per year (a little above the national average of about $1225 yearly). Use the Product Rule and these figures to estimate the rate at which total personal income was rising in the area in 1999. (Round your answer to three decimal places.)
Respond to this Question
Similar Questions

Ecology
What are the types of population density measure and how each may be determined? 
maths
The population of a country is 10 million in 1997 and increasing at a rate of 0.6 million per year. The average annual income of a person during 1997 was 16000 dollars per year and increasing at a rate of 800 dollars per year. How … 
math
I am having trouble solving this problem. In 1994, the population of the Las Vegas metropolitan area was about 1,076,000 with an average annual growth rate of 6.5%. Assume this growth rate continues into the future. I have to estimate … 
8 math
Population density is described as the average number of people per square kilometre. The population density of Canada is approximately 3.5 persons/km2. Use the data in the table. Name a province or territory that has: a) A population … 
Calculas HS
the Museum of Science in Boston displays a running total of the U.S. population. on may 11, 1993, the total was increasing at the rate of 1 person every 14 sec. the displayed population figure at 3:45 PM. that day was 257,313,431. … 
Math
The population of Las Vegas, Nevada in 2000 was 478,000 and is increasing at the rate of 6.28% per year. At this rate, when will the population reach 1 million people? 
College algebra
The population P of a city has been increasing at an annual rate of 1.4%. It's population was 173 thousand in 1992. A. Find a formula for P(t), where t is the year and P is in thousands. B. Estimate the population in 2010, to the nearest … 
Calculus
The population in certain country is growing at the rate of 7 % a year . If the population in the year 1995 was 190 million, (a)determine an exponential expression representing the population as a function of the year. (b) What will … 
CALCULUS PLEASE HELP
The birth rate of a population is b(t) = 2300e0.024t people per year and the death rate is d(t)= 1450e0.018t people per year, find the area between these curves for 0 ≤ t ≤ 10 
calculus 2
The birth rate of a population is b(t) = 2000e^0.022t people per year and the death rate is d(t)= 1460e^0.017t people per year, find the area between these curves for 0 ≤ t ≤ 10. (Round your answer to the nearest integer.)