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A 50.0-kg block is being pulled up a 13 degree slope by a force of 250 N which is parallel to the slope. The coefficient of kinetic friction between the block and the slope is 0.200. What is the acceleration of the block?

  • physics -

    Wb = mg = 50kg * 9.8N/kg = 490N. = Weight of blocki.

    Fb = 490N @ 13deg.
    Fp = 490sin13 = 110.2N. = Force parallel to slope.
    Fv = 490cos13 = 477.4N. = Force perpendicular to slope.

    Fn = Fap - Fp - Ff,
    Fn = 250 - 110.2 - 0.2*477.4 = 44.3N. =
    Net force.

    a = Fn / m = 44.3 / 50 = 0.89m/s^2.

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