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A 7.0 g bullet is fired horizontally into a 1.5 kg block of wood suspended by a thread. The bullet emerges from the block with a speed of 195 m/s, and the block rises to a maximum height of 12 cm.

Find the initial speed of the bullet.

  • PHYSICS HELP!!!!! -

    First calculate the momentum of the block with the bullet hole in it. Ignore the mass loss of wood, since they provide no information on it.

    0.007*Vb = Total Momentum after bullet passes through
    = 195*.007 + sqrt(2*g*H)*1.5

    Solve for Vb, the initial bullet velocity
    H = 0.12 m
    sqrt(2*g*H) is the block velocity after the bullet passes through but before it swings upwards.

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