Physics
posted by Kellie .
A child sits down on one end of a horizontal seesaw of negligible weight, 2.14 m from the pivot point. No one balances on the other side. Find the instantaneous angular acceleration of the seesaw and the tangential linear acceleration of the child.

Physics 
Kellie
I know that the angular acc is g/d or 9.8/2.14=4.58 rad/s^2

Physics 
Matthias Schwartzkopf
the tangential linear acceleration of the child. = g = 9.81m/s^2
instantaneous angular acceleration of the seesaw = a/r = 9.81/1.91 = 5.14rad/s^2 
Physics 
Kellie
where is the 1.91 coming from?

Physics 
Matthias Schwartzkopf
opps, switch that with the 2.14m
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