Chemistry
posted by Hannah .
In the cchemistry lab we conducted an experiment called atomic spectroscopy.
We had to find the color, energy, wavelength, and 1/lamda for Hydrogen, neon, and mercury.
For hydrogen:
red 1.90ev 650nm 1.54e^3
red 2.02ev 610nm 1.64e^3
green 2.30ev 545nm 1.83e^3
for neon:
green 2.30ev 550nm 1.82e^3
red 2.05ev 610nm 1.64e^3
red 1.80ev 690 1.45e^3
yellow 2.12 580 1.72e^3
blue 2.65 470 2.13e^3
for mercury:
green 2.30ev 548 1.823^3
red 2.05 590 1.69e^3
violet 2.85 440 2.27e^3
blue 2.55 470 2.13e^3
yellow 2.15 570 1.75e^3
for the first question we had to derive the equation that would allow us to find Planck's constant from your graph using the formulas
c= lamda X v and E=hv
The teacher said that the equation is h=slope / c
The next question says to show the calculations of Planck's constant, including the unit conversions, for mercury, neon, and hydrogen using the equation created above.
I am not sure how to do this. I do not know where to start.
We had to create graphs for neon and hydrogen on the computer so would i use the slope from there?

Chemistry 
DrBob222
What were your axes? What did you plot on the x axis and what on the y axis?
The slope is delta y/delta x. 
Chemistry 
Hannah
on the x axis was 1/wavelength (nm1) and the y axis was energy(ev). The line for both graphs of neon and hydrogen was positive. So would I pick two points on the graph to find the slope and then do h=slope/c?
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