Chemistry

posted by Hannah

In the cchemistry lab we conducted an experiment called atomic spectroscopy.
We had to find the color, energy, wavelength, and 1/lamda for Hydrogen, neon, and mercury.

For hydrogen:
red 1.90ev 650nm 1.54e^-3
red 2.02ev 610nm 1.64e^-3
green 2.30ev 545nm 1.83e^-3

for neon:
green 2.30ev 550nm 1.82e^-3
red 2.05ev 610nm 1.64e^-3
red 1.80ev 690 1.45e^-3
yellow 2.12 580 1.72e^-3
blue 2.65 470 2.13e^-3

for mercury:
green 2.30ev 548 1.823^-3
red 2.05 590 1.69e^-3
violet 2.85 440 2.27e^-3
blue 2.55 470 2.13e^-3
yellow 2.15 570 1.75e^-3

for the first question we had to derive the equation that would allow us to find Planck's constant from your graph using the formulas
c= lamda X v and E=hv


The teacher said that the equation is h=slope / c

The next question says to show the calculations of Planck's constant, including the unit conversions, for mercury, neon, and hydrogen using the equation created above.

I am not sure how to do this. I do not know where to start.

We had to create graphs for neon and hydrogen on the computer so would i use the slope from there?

  1. DrBob222

    What were your axes? What did you plot on the x axis and what on the y axis?
    The slope is delta y/delta x.

  2. Hannah

    on the x axis was 1/wavelength (nm-1) and the y axis was energy(ev). The line for both graphs of neon and hydrogen was positive. So would I pick two points on the graph to find the slope and then do h=slope/c?

Respond to this Question

First Name

Your Answer

Similar Questions

  1. Physics please explain

    Can you please explain your answer. How did you get blue lamda. Is it because red and green makes blue?
  2. chem lab

    ok I'm having trouble with graphing this chemistry lab. It's on atomic emission spectra. In this experiment we observed the line spectrum of first helium, and here is the data: color: distance: wavelenght: violet 20.35cm light blue …
  3. chem lab

    I'm doing a lab on helium and hydrogen emission spectra. so I got violet 20.35cm blue/green 21.70cm green 22.75 light green 23.08 yellow 27.70 red 31.70 faint red 33.95 and I also have the wavelenghts for helium spectra, its given. …
  4. Chemistry

    Suppose that in your experiment you conducted in lab you neglected to account for pressure due to water vapor in your collected sample of hydrogen gas. How, if at all, would this affect your final value of atomic weight of the metal?
  5. 7th grade

    Susan has red, blue, green, and yellow sweaters. Joanne has green, red, purple, and white sweaters. Diane's sweaters are red, blue, purple, and mauve. Each girl has only one sweater of each color, and will pick a sweater to wear at …
  6. Chemistry

    In the cchemistry lab we conducted an experiment called atomic spectroscopy. We had to find the color, energy, wavelength, and 1/lamda for Hydrogen, neon, and mercury. For hydrogen: red 1.90ev 650nm 1.54e^-3 red 2.02ev 610nm 1.64e^-3 …
  7. Chemistry

    In the cchemistry lab we conducted an experiment called atomic spectroscopy. We had to find the color, energy, wavelength, and 1/lamda for Hydrogen, neon, and mercury. For hydrogen: red 1.90ev 650nm 1.54e^-3 red 2.02ev 610nm 1.64e^-3 …
  8. math

    You have 7 red marbles and 5 green marbles in a bag. You select one, do not replace it then select another. Find P(red,red) and P (green,green). Write probabilites as a percent and rounded to the nearest whole percent. Find P(red,green) …
  9. Math

    A bag of marbles contains only green and red marbles. All of the marbles are the same size. If the probability of selecting a green marble is 1/2. Which is most likely to be the number of green and red marbles in the bag?
  10. statistics

    In a study of red/green color blindness, 850 men and 2500 women are randomly selected and tested. Among the men, 81 have red/green color blindness. Among the women, 5 have red/green color blindness. Test the claim that men have a higher …

More Similar Questions