posted by Neetu
Divide 25 in two parts such that its product is 126
One part must be a multiple of 2 to get the even number. I worked up the even numbers to get the product you indicate, but the closest I could get was 8*17 = 136.
Do you have a typo?
its a question involving simultaneous equations.
1) xy = 126
2) x+ y = 25
Inserting 2) into 1):
(25-x)x = 126
-x^2 +25x-126 = 0
Use the ABC formula, and you get
x= 18 or x = 7
and that is the answer,
because 18 + 7 is 25 and 18 x 7 =126.
i think its a typo....
Divide 25 into two parts such that one of them multiplied by the cube of the other is a maximum. What is the value of the larger part?
FIND THE NUMBER N SUCH THAT WHEN 1/3 OF IT IS ADDED TO 8 THE RESULT IS THE SAME AS WHEN 1/2 OF IT IS SUBTRACTED FROM 18