Before the force is applied (t < 0 on the graph), the particle moves along the X axis with velocity V1 = -7.6 m/s. Find the velocity V2 of the particle after force stops acting on it. (t > 8s)

To find the velocity V2 of the particle after the force stops acting on it, we can use the principle of conservation of momentum.

According to the principle of conservation of momentum, the momentum before the force is applied should be equal to the momentum after the force stops acting on the particle.

The momentum (p) of an object is the product of its mass (m) and velocity (v): p = m * v.

Since the mass of the particle remains constant, the momentum before and after the force is applied can be equated:

m * V1 = m * V2

Where:
V1 = -7.6 m/s (velocity before the force is applied)
V2 = unknown velocity after the force stops acting on the particle

Considering that the mass appears on both sides of the equation, we can cancel it out:

V1 = V2

Therefore, the velocity V2 of the particle after the force stops acting on it is -7.6 m/s.

To find the velocity of the particle after the force stops acting on it (V2), we need to analyze the graph provided.

The graph shows the force applied to the particle as a function of time. However, since only the velocity before and after the force is provided, we will make certain assumptions to solve the question.

Let's consider the graph:

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We know that before the force is applied (t < 0 on the graph), the particle moves along the X axis with velocity V1 = -7.6 m/s. This means that the particle is moving in the negative X direction.

From the given information, we can assume that the force was applied from t = 0s to t = 8s. After t = 8s, the force stops acting on the particle.

Since the force provides an acceleration to the particle, we can conclude that the particle undergoes a change in velocity during the time interval when the force acts on it.

Therefore, the velocity after the force stops acting on the particle will be different from V1.

To find V2, we need to integrate the force-time graph to obtain the change in velocity (∆V) during the time interval (t = 0s to t = 8s) when the force was applied.

Unfortunately, since the force-time graph is not provided, we cannot directly integrate it. Therefore, without further information or additional equations, we cannot determine the exact value of V2 based on the given information.

If you have further details or equations related to the force or acceleration of the particle, please provide them to obtain a more accurate answer.

V2 = -7.6 m/s