algebra
posted by sam .
The width of a rectangle is 4 meters more then 1/3 its lenght. the perimeter is 64. Find the lenght and width

L = Lenght
W = Width
P = Perimeter
P = 64 m
W = 4 + L / 3
P = 2 * ( W + L ) = 64 m
64 = 2 * ( 4 + L / 3 + L ) Divide both sides with 2
32 = 4 + L / 3 + L
32  4 = L / 3 + L
28 = 4 L / 3 Multiply both sides with 3
28 * 3 = 4 L
84 = 4 L Divide both sides with 4
84 / 4 = L
L = 21 m
W = 4 + L / 3
W = 4 + 21 / 3
W = 4 + 7 = 11 m
Lenght = 21 m
Width = 11 m
P = 2 * ( W + L ) = 2 * ( 11 + 21 ) = 2 32 = 64 m 
what is the lenght of a ractangale is 1cm more then twice is width.the diagonal of this rectang is 3 more than twice its find the with of this rectangle ?? and you can put both x on each side the equation should be equal to zero .
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