algebra

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The width of a rectangle is 4 meters more then 1/3 its lenght. the perimeter is 64. Find the lenght and width

  • algebra -

    L = Lenght

    W = Width

    P = Perimeter


    P = 64 m


    W = 4 + L / 3

    P = 2 * ( W + L ) = 64 m

    64 = 2 * ( 4 + L / 3 + L ) Divide both sides with 2

    32 = 4 + L / 3 + L

    32 - 4 = L / 3 + L

    28 = 4 L / 3 Multiply both sides with 3

    28 * 3 = 4 L

    84 = 4 L Divide both sides with 4

    84 / 4 = L


    L = 21 m


    W = 4 + L / 3

    W = 4 + 21 / 3

    W = 4 + 7 = 11 m


    Lenght = 21 m

    Width = 11 m


    P = 2 * ( W + L ) = 2 * ( 11 + 21 ) = 2 32 = 64 m

  • algebra -

    what is the lenght of a ractangale is 1cm more then twice is width.the diagonal of this rectang is 3 more than twice its find the with of this rectangle ?? and you can put both x on each side the equation should be equal to zero .

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