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A right pyramid on a base 4cm square has a slant edge of 6cm.calculate the volume of the pyramid

  • Maths -

    We need the perpendicular height of the pyramid.
    Diagonal of base:
    d^2 = 4^2 + 4^2 = 32
    d= √32 = 4√2

    then h^2 + (2√2)^2 = 6^2
    h^2 = 36 - 8 = 28
    h = √28

    Volume = (1/3) base x height
    = (1/3)(16)(√28) = (32/3)√7 cm^2 or appr. 28.22

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