Using the data collected for part c on your data sheet and assuming the density of the vinegar is 1.00g/mL,
1) calculate the molar concentration of acetic acid (CH3COOH) in the vinegar sample using the average volume of NaOH.
2) calculate the mass percent of acetic acid in the vinegar sample.
Average volume NaOH: 28.94mL
Volume of vinegar: 5.00mL
a) From moles acetic acid = moles NaOH
(acetic acid) = moles/100 g soln.
b) mass percent = moles acetic acid/100 g soln.
To calculate the molar concentration of acetic acid (CH3COOH) in the vinegar sample, we'll first need to determine the number of moles of NaOH used in the titration. Then, by using the balanced chemical equation, we can find the number of moles of acetic acid present in the vinegar. Finally, we'll divide the moles of acetic acid by the volume of vinegar to obtain the molar concentration.
1) Calculate the moles of NaOH
Given that the average volume of NaOH used is 28.94 mL and assuming a 1.00g/mL density of vinegar, we can calculate the mass of NaOH used by multiplying its volume by its density:
Mass of NaOH = Volume of NaOH (mL) * Density of NaOH (g/mL)
Assuming the density of NaOH is also 1.00 g/mL, the mass of NaOH used is 28.94 g.
Next, we'll calculate the moles of NaOH used by dividing its mass by its molar mass:
Moles of NaOH = Mass of NaOH (g) / Molar mass of NaOH (g/mol)
The molar mass of NaOH is 22.99 g/mol for sodium (Na), 16.00 g/mol for oxygen (O), and 1.01 g/mol for hydrogen (H).
Now, we can substitute the values into the equation:
Moles of NaOH = 28.94 g / (22.99 g/mol + 16.00 g/mol + 1.01 g/mol)
2) Calculate the moles of acetic acid (CH3COOH)
Using the balanced chemical equation for the reaction between NaOH and CH3COOH, we know that the molar ratio between NaOH and CH3COOH is 1:1. This means that the moles of NaOH used is equal to the moles of acetic acid (CH3COOH) present in the vinegar.
Moles of acetic acid (CH3COOH) = Moles of NaOH
3) Calculate the molar concentration of acetic acid in the vinegar
To find the molar concentration of acetic acid in the vinegar, we'll divide the moles of acetic acid (CH3COOH) by the volume of vinegar:
Molar concentration of acetic acid (CH3COOH) = Moles of acetic acid / Volume of vinegar (L)
Given that the volume of vinegar is 5.00 mL, we'll need to convert it to liters by dividing by 1000:
Volume of vinegar (L) = 5.00 mL / 1000
Now we can substitute the values into the equation:
Molar concentration of acetic acid = Moles of acetic acid / Volume of vinegar (L)
Calculating the molar concentration of acetic acid in the vinegar depends on the specific values obtained in part c of your data sheet. Please substitute those values to get the final answer.
2) Calculate the mass percent of acetic acid in the vinegar sample
To calculate the mass percent of acetic acid in the vinegar sample, we need to know the mass of acetic acid and the total mass of the vinegar sample.
Since the volume of vinegar is given as 5.00 mL and the density of vinegar is assumed to be 1.00 g/mL, the mass of the vinegar sample is 5.00 g.
Using the molar concentration of acetic acid (obtained in step 1) and the molar mass of acetic acid (60.05 g/mol), we can calculate the mass of acetic acid:
Mass of acetic acid = Molar concentration of acetic acid (mol/L) * Volume of vinegar (L) * Molar mass of acetic acid (g/mol)
Now we can substitute the values into the equation:
Mass of acetic acid = Molar concentration of acetic acid * Volume of vinegar (L) * Molar mass of acetic acid
Finally, the mass percent of acetic acid can be calculated by dividing the mass of acetic acid by the mass of the vinegar sample and multiplying by 100:
Mass percent of acetic acid = (Mass of acetic acid / Mass of vinegar sample) * 100
Again, the final calculation will depend on the specific values obtained in part c of your data sheet.