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The equation x^2+px+q=0, q cannot be equal to 0, has two unequal roots such that the squares of the roots are the same as the two roots. Calculate the product pq.

there is only one number which satisfies "the square of itself is equal to itself": it is 1. (0 is also the other but it is stated that q cannot be equal to 0)
therefore,
(x-1)(x-1) = x^2 + 2x + 1
p = 2
q = 1

hope this helps~ :)

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