Calculus
posted by Kelvin .
An ice cube is melting such that the side of the cube is decreasing at the rate of 1/4 t^2 cm / min. It is given that the side of the cube is 8cm at the start of the experiment. Calculate the length of the side of the cube when t = 4? ( answer 2 2/3 cm)

ds/dt = (1/4) t^2
s = (1/12) t^3 + 8
when t = 4
s =  (1/12)(4*16) + 8
= 16/3 + 24/3
= 8/3
= 2 2/3
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