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precal

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Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.)
2 cos2 θ − cos θ − 1 = 0

  • precal -

    what's the problem. You know how to solve quadratics:

    Let x = cosθ

    2x^2 - x - 1 = 0
    (2x+1)(x-1) = 0

    x = -1/2 or 1
    So,
    cosθ = -1/2 or 1
    . . .

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