How many grams of HCl are produced according to the following equation, H2 + Cl2 = 2 HCl, when 4.0 g of hydrogen reacts completely?
To determine how many grams of HCl are produced when 4.0 g of hydrogen (H2) reacts completely, we need to use stoichiometry.
1. First, we need to calculate the molar mass of hydrogen (H2) and hydrochloric acid (HCl).
- The molar mass of hydrogen (H2) is 2.016 g/mol.
- The molar mass of hydrochloric acid (HCl) is 36.461 g/mol.
2. Next, we can set up a ratio using the balanced equation 2 H2 + Cl2 = 2 HCl.
- The stoichiometric ratio is 2:2 or 1:1. This means that for every 2 moles of H2, we get 2 moles of HCl.
3. Convert the mass of H2 to moles by dividing the given mass by the molar mass of H2:
- Moles of H2 = mass of H2 / molar mass of H2 = 4.0 g / 2.016 g/mol = 1.98 mol
4. Since the ratio is 1:1, the moles of HCl produced will be the same as the moles of H2.
- Moles of HCl = 1.98 mol
5. Finally, we can convert the moles of HCl to grams by multiplying by the molar mass of HCl:
- Mass of HCl = moles of HCl × molar mass of HCl = 1.98 mol × 36.461 g/mol = 72.17 g
Therefore, when 4.0 g of hydrogen reacts completely, 72.17 grams of hydrochloric acid (HCl) are produced.
Follow these steps.
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