posted by sara .
You have 250 mL of a 0.80 M solution of silver nitrate AgNO3 (169.87 g/mol) dissolved in water. How many grams of AgNO3 does the solution contain?
How many moles AgNO3 do you have? That is M x L = moles.
Then moles = grams/molar mass. You know moles and molar mass; solve for grams.
sol.. ist you converted 250 ml in to liter, so it will be 0.25 l
then (0.25l)(0.8 M)(169.87 g/mol)
it will be 33.94 gram
s0 33.94 g Ag-nitrate require to make 250 ml of 0.8 M sol of silver nitrate
Or u can say that 250 ml of 0.8 M sol of silver nitrate contain 33.94 g Ag-nitrate.