PHYSICS

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a car traveling at a constant velocity of 30 m/sec passes an intersection at time t=0 45 seconds later a second car passes the same intersection and its traveling in the same direction at a constant velocity of 55 m/sec.

when does the second car overtake the first car?

how far have the cars traveled when this happens?

  • PHYSICS -

    When car #2 catches up, their distance from starting point will be equal:

    1. d1 = d2,
    30t = 55(t-0.45),
    30t = 55t - 24.75,
    55t - 30t = 24.75,
    25t = 24.75,
    t = 0.99s.

    2. d = V*t = 30 * 0.99 = 29.7m.

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