9 exponent 0+64(3+5)exponent negative 2
Please help me solve this problem.
9^0 + 64(8)^-2
= 1 + 64/8^2
= 1 + 64/64
= 1+1
= 2
How did you get 9^0 to equal 1?
ANY NUMBER that has an exponent of 0 to it is equal to 1, except the number 0.
PLEASE NOTE! if I have a negative number and I have an exponent of 0, then it is always equal to NEGATIVE ONE!
1025
To solve this problem, we need to follow the order of operations (PEMDAS/BODMAS).
Step 1: Simplify within parentheses
Inside the parentheses, we have 3 + 5, which equals 8.
Therefore, our expression becomes: 9^0 + 64(8)^(-2).
Step 2: Simplify exponents
Any number raised to the power of 0 is always 1.
Thus, 9^0 becomes 1.
Our expression now simplifies to: 1 + 64(8)^(-2).
Step 3: Evaluate the exponent outside the parentheses
The exponent -2 means we have to find the reciprocal of 8^2 (8 raised to the power of 2), which is 1/8^2 or 1/64.
Therefore, our expression becomes: 1 + 64(1/64).
Step 4: Perform multiplication
Multiplying 64 by 1/64 gives us 1.
So, our expression further simplifies to: 1 + 1.
Step 5: Perform addition
Adding 1 and 1 together yields the final answer of 2.
Thus, the solution to the expression 9^0 + 64(3 + 5)^(-2) is 2.