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One zero of f(x)=x^3+4x^2+x+c is -3.
a) calculate the value of c.
b)calculate the other zeros.

Ummm, didn't MathMate just do one of these for you? Plug in -3 and evaluate to find c.

Ummmmm, I needed help with the second part

Divide by x+3 and see what you get:

x^3 + 4x^2 + x -6
= (x+3)(x^2 + x - 2)
= (x+3)(x+2)(x-1)

Got it now?

Determine the roots algebraically by factoring.
a) x^3-8x^2-3x+90=0

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