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The polynomial 2x^3+px^2-x+6 has a remainder of zero when divided by x-2. Calculate p.

P(x)=2x^3+px^2-x+6 = (x-2)Q(x)=0

Since (x-2) is a factor of P(x), evalulate P(2) and equate the result to zero:

2(2)^3+p(2)^2-(2)+6 = 0
16+4p-2+6=0
4p=-20
p=-5

Thank you!!!!

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