Algebra
posted by Alexis .
Given the hyperbola (x2/4) – (y2/9) = 1, find the equations for its asymptotes
A. x = (1/3)y, x = (–1/3)y
B. y = (3/2)x, y = (–3/2)x
C. y = (1/3)x, y = (–1/3)x
D. x = (3/2)y, x = (–3/2)y

If you can't recall the formula, just reason it out. As x,y get big, the equation just looks like
x^2/4 = y^2/9
9x^2 = 4y^2
3x = 2y
y = 3/2 x or 3/2 x
Respond to this Question
Similar Questions

math
Find equations for the asymptotes of the hyperbola x2/9  y2/81 = 1 Rewrite the equation as (x/3)^2  (y/9)^2 = 1 When both x and y are very large in absolute value, the "1" on the right is negligible in comparison, so y/9 approaches … 
mathalgebra
10. What are the equations of the asymptotes for the hyperbola? 
mathalgebra
10. What are the equations of the asymptotes for the hyperbola? 
math 30 conics
Hi i was given the equation (y2)^2  x^2/4 =1. I need to find the center, vertices and asymptotes of this hyperbola. I found the center (0,2) and the vertices were tricky but I think they are (0,1) (0,3) but I'm having trouble finding … 
Calculus
Let f(x)=(4x^2 7x +2)/(x^2 16x +63) Find the equations of the horizontal asymptotes and the vertical asymptotes of f(x). If there are no asymptotes of a given type, enter NONE. If there is more than one asymptote of a given type, … 
Math
Given the hyperbola[(x+3)^2/4][(y1)^2/9]=1,find the equations of the asymptotes. 
College algebra
Find the standard form of the equation of the hyperbola with the given characteristics. Foci:(+4,0) or (4,0) Asymptotes: y=4x or y=4x. 
Algebra
HELP! I am not sure how I would even start this problem or solve it. A hyperbola with a horizontal transverse axis contains the point at (4, 3). The equations of the asymptotes are yx=1 and y+x=5 Write an equation for the hyperbola. 
trig help
Find the equation of the hyperbola satisfying the given conditions. Vertices at (5, 1) and (7, 1); asymptotes (y  1) = 1/3(x + 1) and (y  1) = 1/3(x + 1) 
Math
find the vertices, foci, equations of the asymptotes, length of LR, and the graph of the hyperbola x^24y^2+4x+24y=28