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PERIMETER OF A RECTANGLE IS 32CM AND AREA IS 55CM FIND THE LENGHT.

  • trig -

    l+w = 16 --> l=16-w

    lw=55
    w(16-w)=55
    16w - w^2=55
    w^2-16w+55=0
    (w-5)(w-11)=0w=5 or w=11

    we have a symmetric solution, that is,
    if w=5 , then l=11
    if w=11, then l = 5

    the rectangle is 5 by 11
    usually the longer side is called the length
    so the length is 11 cm

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