Chemistry for Engineers
posted by Austin .
How many mL of .2475M Sr(OH)_2 solution are needed to neutralize 25 mL of 0.1542M HCL solution in the reaction
2HCl + Sr(OH)_2 -> SrCl_2 + 2H_2_O
moles HCl = M x L = ?
Using the coefficients in the balanced equation, convert moles HCl to moles Sr(OH)2.
Then M Sr(OH)2 = moles Sr(OH)2/L Sr(OH)2. YOu know M and moles, solve for L and convert to mL.