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ball thrown up from top of 96 foot high tower with initial velocity of 80 ft/s.

when does ball reach max height and how high is it at that time?

  • math -

    v = 80 - 32t
    v = 0 is where the ball stops rising and starts falling

    0 = 80 - 32t
    t = 2.5s

    h = 96 + 80t - 16t^2
    = 96 + 80*2.5 - 16*6.25
    = 196 ft

  • math -

    what is the -32 t? I think I undersaand the rest.

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