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In the triangle ABC ,AB=11 cm ,BC=9cm an CA=10 cm..Find area of the triangle ABC

  • math -

    If you don't have access to heron's formula, then you can use law of sines

    sin a/9 = sin b/10 = sin c/11
    c = 180-(a+b)

    work on that a while and you will find sin b = .8578

    Now, h/9 = sin b
    so h = 9 sin b

    area = 1/2 * 11 * 9 * .8578 = 42.46

    Heron's formula says that
    with s = (a+b+c)/2

    area = sqrt(15*4*5*6) = 42.43

    looks good to me.

  • math -

    WROOOOOONG

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