algebra
posted by Sejul .
length of rectantular rug is 7/6 its width.
rug is placed on floor with 1 foot margin all around.
area of floor is 4 times that of margin.
find the dimensions of the room.

length of rug = 7x
width of rug = 6x , (that avoids fractions)
floor is (7x+2) by (6x+2)
area of margin = (7x+2)(6x+2)  42x^2
floor is 4 times the margin
(7x+2)(6x+2) = 4[(7x+2)(6x+2)  42x^2 ]
42x^2 + 26x + 4 = 4[42x^2 + 26x + 4  42x^2]
42x^2  78x  12 = 0
7x^2  13x  2 = 0
(x2)(7x+1) = 0
x = 2 or a negative
so the floor is
7x+2 by 6x+2 or
16 by 14 or 224 ft^2
and the rug is (7x)(6x) = 168 ft^2
margin = 224168 = 56
is 4(56) = 224 ??, YES
The room is 16 ft by 14 ft
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