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New question: A baseball was 2.74 feet above ground when it was hit. It reached a max. height of 116.3ft when it was approx 215.3 ft away from where he hit the ball. The ball lands after travelling a ground distance of approx 433.1 ft.

Find an equation of form y = A(x-h)^2 + k where vertex is (h,k) and constant A is a scaling factor.

So the vertex is (215.3, 116.3).

Plugging in I have
y = A (x-215.3)^2 + 116.3
Using point (0, 2.74), I have
2.74 = A (0-215.3)^2 + 116.3
2.74 = A (46354.09 + 116.3)
2.74 = A 46,470.39
0.000059 = A

**** shouldn't my A be negative to get a hill shape?

Yes. You made a mistake, placing the right parenth ) the right of the 116.3.

A will be negative if you solve
46354 A = 2.74 - 116.3 = -113.56
A = -0.0024498

Check: when x = 433.1,
y = -0.0024498(433.1-215.3)^2+116.3
= -116.2 +116.3 = 0.01
That's close enough.

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