Post a New Question

Calculus

posted by .

What is the limit of this function as x approaches 0?
cos(x) - 1 / x
From what I gather, the limit is equal to 0, since on the right, the function approaches from negative values close to zero and on the left, it approaches 0 with positive values close to zero. Would this be correct?

  • Calculus -

    There are several ways to get at this limit.

    Using L'Hopital's Rule, if f/g = 0/0, then the limit is f'/g'

    In this case, -sin/1 = 0
    You are correct.

    Then, the cosine can be expressed as an infinite series:

    1 - x^2 / 2! + x^4 / 4! - ...

    so cos(x) - 1 = -x^2/2! + x^4/4! - ...

    Divide that by x, and you are left with

    -x/2! + x^3/4! - ...

    which are all just powers of x. When x=0, they all vanish, so the limit is 0.

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question