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A ball is thrown upward at a speed v0 at an angle of 59.0¢ª above the horizontal. It reaches a maximum height of 8.7 m. How high would this ball go if it were thrown straight upward at speed v0?

  • physics -

    Yo = ver. = Vosin59 = 0.857Vo. = ver.
    component of Vo.

    Vf^2 = Yo^2 + 2g*d,
    Yo^2 = Vf^2 - 2g*d,
    Yo^2 = 0 + 19.6*8.7 = 170.52,
    Yo = 13.06m/s.

    Yo = 0.857Vo = 13.06m/s,
    0.857Vo = 13.06,
    Vo = 15.2m/s.

    h = (Vf^2 - Vo^2) / 2g,
    h = (0 - (15.2)^2) / -19.6 = 11.85m.

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